task2-2.c

#include<stdio.h>
#include<math.h>
int main()
{
    double x,ans;
    
    while(scanf("%lf",&x)!=EOF)
    {
        ans = pow(x,365);
        printf("%.2f的365次方:%.2f\n",x,ans);
        printf("\n");
    }
 
    
    return 0;
}