# 【BZOJ1051】[HAOI2006]受欢迎的牛

bzoj

## 题解

#include<iostream>
#include<cstdio>
#include<cstdlib>
#include<cstring>
#include<cmath>
#include<algorithm>
using namespace std;

inline int gi(){
register int data=0, w = 1;
register char ch=0;
while (ch != '-' && (ch > '9' || ch < '0')) ch = getchar();
if (ch == '-') w = -1 , ch = getchar();
while (ch >= '0' && ch <= '9') data = (data << 1) + (data << 3) + (ch ^ 48), ch = getchar();
return w * data;
}
#define MAX_N 10005
#define MAX_M 50005
struct Edge {
int to, next;
} e[MAX_M];
int h[MAX_N], cnt;
int n, m;
void Add_Edge(int u, int v) {
e[cnt].to = v, e[cnt].next = h[u], h[u] = cnt++;
}
int tim = 0, num = 0, top = 0;
int low[MAX_N], dfn[MAX_N], color[MAX_N], st[MAX_N];
int tot[MAX_N];
void tarjan(int x) {
low[x] = dfn[x] = ++tim;
st[++top] = x;
for (register int i = h[x]; ~i; i = e[i].next) {
if (!dfn[e[i].to]) {
tarjan(e[i].to);
low[x] = min(low[x], low[e[i].to]);
} else if (!color[e[i].to])
low[x] = min(low[x], dfn[e[i].to]);
}
if (low[x] == dfn[x]) {
color[x] = ++num;
tot[num]++;
while (st[top] != x) {
color[st[top]] = num;
tot[num]++;
--top;
}
--top;
}
}
int d[MAX_N];
int main () {
memset(h, -1, sizeof(h));
n = gi(), m = gi();
for (register int i = 1; i <= m; i++) {
int u = gi(), v = gi();
}
for (register int i = 1; i <= n; i++)
if (!dfn[i]) tarjan(i);
int ans = 0, F = 0;
for (register int x = 1; x <= n; x++)
for (int i = h[x]; ~i; i = e[i].next)
if (color[x] != color[e[i].to]) d[color[x]]++;
for (register int i = 1; i <= num; i++) {
if (d[i] == 0) F++, ans = tot[i];
}
if (F == 1) printf("%d\n", ans);
else printf("0\n");
return 0;
}

posted @ 2018-12-26 15:01  heyujun  阅读(85)  评论(0编辑  收藏