python10：函数作业

1.接受n个数字，求这些参数数字的和

#写函数，接收n个数字，求这些参数数字的和
# def Sum(*num):
#     sum = 0
#     for item in num:
#         sum+=item
#         print(sum)
#         pass
#     return sum
# pass
# result=Sum(1,2,3,4,5,6,7,8,9,10)
# print(result)

2，找出传入的列表或者元组奇数位对应的元素，并返回一个新的列表

# def newlist(list):
#     # print(len(list))
#     # print(list[0])
#     new=[]
#     i=0
#     while i<=len(list)-1:
#         new.append(list[i])
#         i+=2
#         pass
#     return new
# pass
#
# print(newlist([1,2,3,4,5,6,7,8,9,10]))

3.检查传入字典的每一个value的长度，如果大于二，那么仅保留前两个长度的内容，并将新内容返回给调用者。

def dicFunc(ziDian):
    new={}
    for key,value in ziDian.items():
        if len(value)>2:
            new[key]=value[0:2]
            pass
        else:
            new[key]=value
            pass
        pass
    return new
pass

zidian={'name':'being','age':'223','hoppy':['sing','jump','basketball']}
print(dicFunc(zidian))