实验5

试验任务1_1

程序源代码

#include <stdio.h>
#define N 4
int main()
{
    int x[N] = {1, 9, 8, 4};
    int i;
    int *p;
 
// 方式1:通过数组名和下标遍历输出数组元素
    for (i = 0; i < N; ++i)
        printf("%d", x[i]);
    printf("\n");
 
// 方式2:通过指针变量遍历输出数组元素 (写法1)
    for (p = x; p < x + N; ++p)
        printf("%d", *p);
    printf("\n");
 
// 方式2:通过指针变量遍历输出数组元素(写法2)
    p = x;
    for (i = 0; i < N; ++i)
        printf("%d", *(p + i));
    printf("\n");
 
// 方式2:通过指针变量遍历输出数组元素(写法3)
    p = x;
    for (i = 0; i < N; ++i)
        printf("%d", p[i]);
    printf("\n");
 
    return 0;
}

运行截图

 

试验任务1_2

程序源代码

#include <stdio.h>
int main()
{
    int x[2][4] = {{1, 9, 8, 4}, {2, 0, 4, 9}};
    int i, j;
    int *p; // 指针变量,存放int类型数据的地址
    int(*q)[4]; // 指针变量,指向包含4个int型元素的一维数组
 
// 使用数组名、下标访问二维数组元素
    for (i = 0; i < 2; ++i)
    {
        for (j = 0; j < 4; ++j)
            printf("%d", x[i][j]);
        printf("\n");
    }
 
// 使用指针变量p间接访问二维数组元素
    for (p = &x[0][0], i = 0; p < &x[0][0] + 8; ++p, ++i)
    {
        printf("%d", *p);
        if ((i + 1) % 4 == 0)
            printf("\n");
    }
 
// 使用指针变量q间接访问二维数组元素
    for (q = x; q < x + 2; ++q)
    {
        for (j = 0; j < 4; ++j)
            printf("%d", *(*q + j));
        printf("\n");
    }
 
    return 0;
}

 

运行截图

 

试验任务2_1

程序源代码

#include <stdio.h>
#include <string.h>
#define N 80
int main()
{
    char s1[] = "Learning makes me happy";
    char s2[] = "Learning makes me sleepy";
    char tmp[N];
 
    printf("sizeof(s1) vs. strlen(s1): \n");
    printf("sizeof(s1) = %d\n", sizeof(s1));
    printf("strlen(s1) = %d\n", strlen(s1));
     
    printf("\nbefore swap: \n");
    printf("s1: %s\n", s1);
    printf("s2: %s\n", s2);
 
    printf("\nswapping...\n");
    strcpy(tmp, s1);
    strcpy(s1, s2);
    strcpy(s2, tmp);
 
    printf("\nafter swap: \n");
    printf("s1: %s\n", s1);
    printf("s2: %s\n", s2);
 
    return 0;
}

 

运行截图

 

试验任务2_2

程序源代码

#include <stdio.h>
#include <string.h>
#define N 80
int main()
{
    char *s1 = "Learning makes me happy";
    char *s2 = "Learning makes me sleepy";
    char *tmp;
 
    printf("sizeof(s1) vs. strlen(s1): \n");
    printf("sizeof(s1) = %d\n", sizeof(s1));
    printf("strlen(s1) = %d\n", strlen(s1));
 
    printf("\nbefore swap: \n");
    printf("s1: %s\n", s1);
    printf("s2: %s\n", s2);
 
    printf("\nswapping...\n");
    tmp = s1;
    s1 = s2;
    s2 = tmp;
 
    printf("\nafter swap: \n");
    printf("s1: %s\n", s1);
    printf("s2: %s\n", s2);
 
    return 0;
}

 

运行截图

 

存放的是地址。计算类型长度。统计的是其所包含的字符串的长度。

可以。这个是直接在地址上进行修改。

交换的是各自的地址。没有。

 实验任务3
 
程序源代码
 

#include<stdio.h>
#include<stdlib.h>


void str_cpy(char *target,const char *source);
void str_cat(char *str1,char *str2);

int main()
{
char s1[80],s2[20]="1984";

str_cpy(s1,s2);
puts(s1);

str_cat(s1,"Animal Farm");
puts(s1);
system("pause");
return 0;}

void str_cpy(char *target, const char *source)
{while(*target++=*source++)
;
}


void str_cat(char *str1, char *str2)
{
while(*str1)
str1++;
while(*str1++=*str2++)
;}

 

 

运行截图

 

实验任务4
程序源代码
 
#include<stdio.h>
#include<stdlib.h>
#define N 80
int func(char *);
 
int main()
{
    char str[80];
 
    while(gets(str)!=NULL)
    {
        if(func(str))
            printf("yes\n");
        else
            printf("no\n");
    }
    system("pause");
    return 0;}
 
 
int func(char *str)
{
    char *begin, *end;
 
    begin = end = str;
 
    while(*end)
        end++;
 
    end--;
 
    while(begin<end)
    {
        if(*begin!=*end)
            return 0;
        else
        {
            begin++;
            end--;
        }
    }
 
    return 1;}

 

运行截图
 

 

实验任务5
 
程序源代码
 
#include <stdio.h>
#define N 80
void func(char *);
 
int main()
{
    char s[N];
 
    while (scanf("%s", s) != EOF)
    {
        func(s);
        puts(s);
    }
 
    return 0;
}
 
void func(char *str)
{
    int i;
    char *p1, *p2, *p;
 
    p1 = str;
    while (*p1 == '*')
        p1++;
    
    p2 = str;
    while (*p2)
        p2++;
    p2--;
 
    while (*p2 == '*')
        p2--;
 
    p = str;
    i = 0;
    while (p < p1)
    {
        str[i] = *p;
        p++;
        i++;
    }
 
    while (p <= p2)
    {
        if (*p != '*')
        {
            str[i] = *p;
            i++;
        }
        p++;
    }
 
    while (*p != '\0')
    {
        str[i] = *p;
        p++;
        i++;
    }
 
    str[i] = '\0';
}

 

运行截图
 

 

试验任务6_1
 
程序源代码
 
#include<stdio.h>
#include<string.h>
#include<stdlib.h>
void sort(char *name[],int n);
 
int main()
{
    char *course[4]={"C Program",
                     "C++ Object Oriented Program",
                     "Operating System",
                     "Data Structure and Algorithms"};
    int i;
 
    sort(course, 4);
 
    for(i=0;i<4;i++)
        printf("%s\n",course[i]);
    system("pause");
    return 0;}
 
void sort(char *name[], int n)
{
    int i,j;
    char *tmp;
 
    for(i=0;i<n-1;++i)
        for(j=0;j<n-1-i;++j)
            if(strcmp(name[j],name[j+1])>0)
            {
                tmp = name[j];
                name[j] = name[j+1];
                name[j+1]=tmp;
            }
}

 

运行截图
 

 

试验任务6_2
 
程序源代码
 
#include <stdio.h>
#include <string.h>
void sort(char *name[], int n);
 
int main()
{
    char *course[4] = {"C Program",
                       "C++ Object Oriented Program",
                       "Operating System",
                       "Data Structure and Algorithms"};
    int i;
 
    sort(course, 4);
    for (i = 0; i < 4; i++)
        printf("%s\n", course[i]);
  
    return 0;
}
 
void sort(char *name[], int n)
{
    int i, j, k;
    char *tmp;
 
    for (i = 0; i < n - 1; i++)
    {
        k = i;
        for (j = i + 1; j < n; j++)
            if (strcmp(name[j], name[k]) < 0)
                k = j;
 
    if (k != i)
    {
        tmp = name[i];
        name[i] = name[k];
        name[k] = tmp;
    }
  }
}

 

运行截图

交换的是指针变量的值

 实验任务7
 
程序源代码
 
#include <stdio.h>
#include <string.h>
#define N 5
int check_id(char *str); // 函数声明
 
int main()
{
    char *pid[N] = {"31010120000721656X",
                    "330106199609203301",
                    "53010220051126571",
                    "510104199211197977",
                    "53010220051126133Y"};
    int i;
 
    for (i = 0; i < N; ++i)
        if (check_id(pid[i])) // 函数调用
            printf("%s\tTrue\n", pid[i]);
        else
            printf("%s\tFalse\n", pid[i]);
 
    return 0;
}
 
int check_id(char *str) {
    char *p;
    int i;
 
    p = str;
 
    while((*p >= '0' && *p <= '9')||*p=='X')
            p++;
 
    if(*p == '\0' && strlen(str) == 18)
        return 1;
    else
        return 0;
}

 

运行截图
 

 

实验任务8
 
程序源代码
 
#include <stdio.h>
#define N 80
void encoder(char *s); // 函数声明
void decoder(char *s); // 函数声明
int main()
{
char words[N];
printf("输入英文文本: ");
gets(words);
printf("编码后的英文文本: ");
encoder(words); // 函数调用
printf("%s\n", words);
printf("对编码后的英文文本解码: ");
decoder(words); // 函数调用
printf("%s\n", words);
return 0;
}
 
void encoder(char *s) {
    while(*s) {
        if(*s >= 65 && *s <= 90|| *s >= 97&& *s <= 122) {
            *s = *s + 1;
            s++; continue;
        }
        else if(*s == 90|| *s == 122) {
            *s = *s - 25;
            s++; continue;
        }
        s++;
    }
    return;
}
void decoder(char *s) {
    while(*s) {
        if(*s >= 66 && *s <= 90 || *s >= 98 && *s <= 122) {
            *s = *s - 1;
            s++; continue;
        }
        else if(*s == 65|| *s == 97) {
            *s = *s + 25;
            s++; continue;
        }
        s++;
    }
    return;
}

 

运行截图

 

posted @ 2023-05-08 23:08  &YT  阅读(21)  评论(0编辑  收藏  举报