随笔分类 -  shell

摘要:#!/bin/bashtest1=""for test in $(cat morningglory.2023-03-03.0.log |grep have | sed -r 's/.*have(.*)role.*/\1/'| sed s/[[:space:]]//g)do test1="$test" 阅读全文
posted @ 2023-03-03 16:11 HarsonLee 阅读(220) 评论(0) 推荐(0)