实验四
任务1.1
#include <stdio.h> #define N 4 int main() { int a[N] = {2, 0, 2, 2}; char b[N] = {'2', '0', '2', '2'}; int i; printf("sizeof(int) = %d\n", sizeof(int)); printf("sizeof(char) = %d\n", sizeof(char)); printf("\n"); // 输出数组a中每个元素的地址、值 for (i = 0; i < N; ++i) printf("%p: %d\n", &a[i], a[i]); printf("\n"); // 输出数组b中每个元素的地址、值 for (i = 0; i < N; ++i) printf("%p: %c\n", &b[i], b[i]); printf("\n"); // 输出数组名a和b对应的值 printf("a = %p\n", a); printf("b = %p\n", b); return 0; }
1.是连续的,每个元素占4个内存字节单元
2.是连续的,每个元素占1个内存字节单元
3.都是一样的
任务1.2
#include <stdio.h> #define N 2 #define M 3 int main() { int a[N][M] = {{1, 2, 3}, {4, 5, 6}}; char b[N][M] = {{'1', '2', '3'}, {'4', '5', '6'}}; int i, j; // 输出二维数组a中每个元素的地址和值 for (i = 0; i < N; ++i) for (j = 0; j < M; ++j) printf("%p: %d\n", &a[i][j], a[i][j]); printf("\n"); // 输出二维数组a中每个元素的地址和值 for (i = 0; i < N; ++i) for (j = 0; j < M; ++j) printf("%p: %c\n", &b[i][j], b[i][j]); return 0; }
1.是,4个
2.是,1个
任务2
#include <stdio.h> int days_of_year(int year, int month, int day); int main() { int year, month, day; int days; while (scanf("%d%d%d", &year, &month, &day) != EOF) { days = days_of_year(year, month, day); printf("%4d-%02d-%02d是这一年的第%d天.\n\n", year, month, day, days); } return 0; } int days_of_year(int year, int month, int day) { int i; int mon[] = { 0,31,28,31,30,31,30,31,31,30,31,30,31 }; int s = 0; for (i = 1; i < month; ++i) s = s + mon[i]; s = s + day; if ((year % 4 == 0 && year % 100 != 0 || year % 400 == 0) && month >= 3) s++; return s; }
任务3
#include<stdio.h> #define N 5 void input(int x[], int n); void output(int x[], int n); double average(int x[], int n); void sort(int x[], int n); int main() { int scores[N]; double ave; printf("录入%d个分数:\n", N); input(scores, N); printf("\n输入课程分数:\n"); output(scores, N); printf("\n课程分数处理:计算均分、排序...\n"); ave = average(scores, N); sort(scores, N); printf("\n输出课程均分:%.2f\n", ave); printf("\n输出课程分数(高->低):\n"); output(scores, N); return 0; } void input(int x[], int n) { int i; for (i = 0; i < n; ++i) scanf("%d", &x[i]); } void output(int x[], int n) { int i; for (i = 0; i < n; ++i) printf("%d ", x[i]); printf("\n"); } double average(int x[], int n) { int sum = 0, i; double ave; for (i = 0; i < n; ++i) { sum += x[i]; } ave = 1.0*sum / N; return ave; } void sort(int x[], int n) { int i, j, temp; for (i = 1; i < n; i++) { for (j = 0; j < n-1; j++) { if (x[j] < x[j + 1]) { temp = x[j]; x[j] = x[j + 1]; x[j + 1] = temp; } } } }
任务4
#include<stdio.h> void dec2n(int x, int n); int main() { int x; printf("输入一个十进制整数:"); scanf("%d", &x); dec2n(x, 2); dec2n(x, 8); dec2n(x, 16); return 0; } void dec2n(int x, int n) { int a[1000]; int i; for (i = 0;x!=0; i++) { a[i] = x % n; x = x / n; } for (i = i - 1; i >= 0; i--) { if (a[i] == 10) printf("%c", 'A'); else if (a[i] == 11) printf("%c", 'B'); else if (a[i] == 12) printf("%c", 'C'); else if (a[i] == 13) printf("%c", 'D'); else if (a[i] == 14) printf("%c", 'F'); else if (a[i] == 15) printf("%c", 'E'); else if (a[i] <10) printf("%d", a[i]); } printf("\n"); }
任务5
#include<stdio.h> #define N 100 int main() { int n, i, j, x[N][N]; printf("Enter n:"); while (scanf("%d", &n) != 0) { for (i = 0; i <= n - 1; i++) { for (j = 0; j <= n - 1; j++) { if (i <= j) x[i][j] = i + 1; else x[i][j] = j + 1; printf("%2d", x[i][j]); } printf("\n"); } printf("\nEnter n:"); } return 0; }
任务6
#include<stdio.h> #define N 80 int main() { char views1[N] = "hey, c, i hate u."; char views2[N] = "hey, c, i love u."; char temp; int i = 0; printf("original views:\n"); printf("views1: %s\n",views1); printf("views2: %s\n",views2); while(views1[i]!='\0') { temp = views1[i]; views1[i] = views2[i]; views2[i] = temp; i++; } printf("\nswapping...\n"); printf("views1: %s\n",views1); printf("views2: %s\n",views2); return 0; }
任务7
#include<stdio.h> #include<string.h> #define N 5 #define M 20 void bubble_sort(char str[][M], int n); int main() { char name[][M] = { "Bob","Bill","Joseph","Taylor","George" }; int i; printf("输出初始名单:\n"); for (i = 0; i < N; i++) printf("%s\n", name[i]); printf("\n排序中…\n"); bubble_sort(name, N); printf("\n按字典输出名单:\n"); for (i = 0; i < N; i++) printf("%s\n", name[i]); return 0; } void bubble_sort(char str[][M], int n) { int i, j; char t[10]; for(i=0;i<n-1;i++) for(j=0;j<n-i-1;j++) if (strcmp(str[j], str[j + 1]) > 0) { strcpy(t, str[j]); strcpy(str[j], str[j + 1]); strcpy(str[j + 1], t); } }