斐波拉契数列

def fib(max):
n = 0
a = 0
b = 1
while n < max:
print(b)
s = (b, a + b)
a = s[0]
b = s[1]
n = n + 1
posted @ 2018-07-10 17:20  老僧观天下  阅读(134)  评论(0编辑  收藏  举报