JS 10位、13位时间戳转日期

(注意:下面的date可以加个判断是10位时间戳还是13位时间戳来进行编码是否需要*1000; param为你要转换的时间戳变量
    if(param.length == 10){
        let date = new Date(parseInt(param) * 1000);
    }else if(param.length == 13){
         let date = new Date(parseInt(param));
    }
)

 

 

 

let date = new Date(parseInt(res.data.rows[i].time) * 1000);
let y = date.getFullYear();
let m = date.getMonth() + 1;
m = m < 10 ? ('0' + m) : m;
let d = date.getDate();
d = d < 10 ? ('0' + d) : d;
let h = date.getHours();
h = h < 10 ? ('0' + h) : h;
let minute = date.getMinutes();
let second = date.getSeconds();
minute = minute < 10 ? ('0' + minute) : minute; second = second < 10 ? ('0' + second) : second;
// console.log( y + '-' + m + '-' + d + ' ' + ' ' + h + ':' + minute + ':' + second)
let dates = y + '-' + m + '-' + d + ' ' + ' ' + h + ':' + minute + ':' + second;// 封装的时间戳转换日期函数

dateTrans(date) {
    let _date = new Date(parseInt(date));
    let y = _date.getFullYear();
    let m = _date.getMonth() + 1;
    m = m < 10 ? ('0' + m) : m;
    let d = _date.getDate();
   d = d < 10 ? ('0' + d) : d;
   let h = _date.getHours();
    h = h < 10 ? ('0' + h) : h;
    let minute = _date.getMinutes();
    let second = _date.getSeconds();
     minute = minute < 10 ? ('0' + minute) : minute; second = second < 10 ? ('0' + second) : second;
   // console.log( y + '-' + m + '-' + d + ' ' + ' ' + h + ':' + minute + ':' + second)
    let dates = y + '-' + m + '-' + d;

    return dates;
},

posted @ 2020-07-13 11:01  番茄匠Amy  阅读(1755)  评论(0编辑  收藏  举报