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&(与)、| (或)、^(异或)、~ (非/取反) 判断奇偶数 x&1=1为奇数 =0为偶数 原因:奇数最后一位是1,&1后为1,偶数最后一位为0,&1后为0 1.将整数的二进制奇偶位互换 package 蓝桥杯算法; import java.util.Scanner; /** * 例如 1001 阅读全文
posted @ 2021-08-06 21:24
guoyuxin3
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ACboy needs your help again! Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 22399 Accepted Submi 阅读全文
posted @ 2021-08-06 18:34
guoyuxin3
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Text Reverse Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 64691 Accepted Submission(s): 24779 阅读全文
posted @ 2021-08-06 17:48
guoyuxin3
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圆桌问题 Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 65535/32768 K (Java/Others)Total Submission(s): 15263 Accepted Submission(s): 5166 Problem D 阅读全文
posted @ 2021-08-06 17:19
guoyuxin3
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