[LeetCode] 7. Reverse Integer

Reverse digits of an integer.

public class Solution {
    public int reverse(int x) {
        
        long lx = x;
        long nx = 0;
        while (lx != 0) {
            nx = nx * 10 + lx % 10;
            lx /= 10;
        }
        
        return (int)((nx > Integer.MAX_VALUE || nx < Integer.MIN_VALUE) ? 0 : nx);
    }
}