php配色器

近来苦于配色，今日思之以解决方案，颜色过渡，遂美

$one = intval(substr($basecolor,0,2),16);
$two = intval(substr($basecolor,2,2),16);

echo "<table id=\"colorT\">";

for ($jk=0;$jk<=0x0F ;) {
	for ($k=0;$k<=0x0F ;) {
		$c1 = 0x1000000+ $one*16*16*16*16+$two+$jk*16*16*16+$k*16*16; //FF00FF	
		$c2 = 0x1000000+ $one*16*16*16*16+$two*16*16+$jk*16+$k;	//FFFF00
		$c3 = 0x1000000+ ($jk*16+$k)*16*16*16*16+$two*16*16+$one;	//00FFFF
		$c1=dechex($c1);$c2=dechex($c2);$c3=dechex($c3);
		$color1[] = substr($c1,1);
		$color2[] = substr($c2,1);	
		$color3[] = substr($c3,1);
		//$color = dechex($color);
		//echo "<td bgcolor=\"#{$color}\"> </td><td>#{$color}</td>";
		$k+=0x1E;
	}//fork
	$jk+=$step;
}//for jk

$color1table = "";$color2table = "";$color3table = "";
$n=count($color2);

$lines = intval($n/$loop)+1;

for ($j=0;$j<=$lines ;$j++ ) {
	$color1table .="<tr>\n";
	$color2table .="<tr>\n";
	$color3table .="<tr>\n";
	for ($i=0;$i<$loop ;$i++ ) {
		$k = $loop*$j+$i;
		if($k>=$n)break 2;
		$color1bg = $color1[$k];
		$color2bg = $color2[$k];
		$color3bg = $color3[$k];
		$color1table .="<td bgcolor=\"#".$color1bg."\"> </td><td>#".$color1bg."</td>\n";
		$color2table .="<td bgcolor=\"#".$color2bg."\"> </td><td>#".$color2bg."</td>\n";
		$color3table .="<td bgcolor=\"#".$color3bg."\"> </td><td>#".$color3bg."</td>\n";		
	}//fori  
	$color1table .="</tr>\n";	$color2table .="</tr>\n";	$color3table .="</tr>\n";	
}//forj

echo $color1table;
echo $color2table;
echo $color3table;

for ($i=0xFF;$i<=0xFF ;$i++) {
	for ($j=0xFF;$j<=0xFF ;$j++) {
			for ($jk=0;$jk<=0x0F ;$jk++) {
			//echo"<tr>\n";
				for ($k=0;$k<=0x0F ;) {
					$color =0x1000000+$i*16*16*16*16+$j+$jk*16*16*16+$k*16*16; //FF00FF	
					//$color =0x1000000+$i*16*16*16*16+$j*16*16+$jk*16+$k;	//FFFF00
					//$color =0x1000000+($jk*16+$k)*16*16*16*16+$j*16*16+$i;	//00FFFF
					$color = dechex($color);
					$color = substr($color,1);
					//echo "<td bgcolor=\"#{$color}\"> </td>";
					$k+=0x1E;
				}//fork
				$jk+=2;
			//echo "</tr>\n";
			}//for jk
	}//forj
}//fori
 echo "</table>";   
}//if checked
?>

<form method=post action="?">
基于颜色应该做到以单字节为基本。目前是4字节。

基于颜色： <input type="text" name="basecolor" value="ffff" size="40" />

颜色跳距离:<input type="text" name="step" value="1" size="40" />
显示列:<select name="loop">
<option value="1">1</option><option value="2">2</option><option value="3">3</option><option value="4">4</option>
</select>
 <input type="hidden" name="checked" value="1" />
<input type="submit" value="submit" />
</form>

Posted on 2005-10-14 16:59 古代阅读(498) 评论(0) 收藏举报

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