BZOJ4916: 神犇和蒟蒻 杜教筛

#include<bits/stdc++.h>
#define setIO(s) freopen(s".in","r",stdin) 
#define ll long long  
#define maxn 10000005  
using namespace std;  
const long long mod=1000000007;   
map<int,ll>getf;  
int cnt; 
int vis[maxn]; 
int prime[maxn];
ll  phi[maxn]; 
ll sumf[maxn];   
ll rev6; 
int N; 
inline ll qpow(ll base,ll k)
{
	ll tmp=1; 
	while(k)
	{
		if(k&1) tmp=tmp*base%mod;  
		base=base*base%mod; 
		k>>=1; 
	}
	return tmp;  
}
inline void prepare()
{ 
	rev6=qpow(1ll*6, mod-2);          
	phi[1]=1; 
	for(int i=2;i<=N;++i) 
	{
		if(!vis[i]) prime[++cnt]=i, phi[i]=i-1;                              
		for(int j=1;j<=cnt&&1ll*i*prime[j]<=N;++j) 
		{
			vis[i*prime[j]]=1; 
			if(i%prime[j]==0) 
			{
				phi[i*prime[j]]=phi[i]*prime[j];          
				break; 
			}
			phi[i*prime[j]]=phi[i]*phi[prime[j]];      
		}
	}     
	for(int i=1;i<=N;++i) sumf[i]=(sumf[i-1]+1ll*phi[i]*i%mod)%mod;            
}   
ll Sum(ll n)  { return (n*(n+1)%mod*(n+n+1))%mod*rev6%mod;  }
ll Get(int n)
{
	if(n<=N) return sumf[n];             
	if(getf[n]) return getf[n];   
	ll re=Sum(n), tmp; 
	int i,j; 
	for(i=2;i<=n;i=j+1) 
	{ 
		j=n/(n/i);    
		tmp=1ll*(i+j)*(j-i+1)/2%mod; 
		tmp=(tmp*Get(n/i))%mod; 
		tmp%=mod;  
		re=(re-tmp+mod)%mod;         
	}
	return getf[n]=re;                 
}
int main()
{ 
	//   setIO("input");     
	int n; 
	scanf("%d",&n);  
	N=min(10000002,n); 
	prepare();  
	printf("%d %lld\n",1,Get(n));   
	return 0;
}

  

posted @ 2019-07-10 17:16  EM-LGH  阅读(125)  评论(0编辑  收藏  举报