python 最简单的 websocket 会显服务
初次链接会显示 欢迎
import asyncio
import websockets
async def echo(websocket, path):
# 发送 welcome 消息
await websocket.send("welcome")
async for message in websocket:
await websocket.send(message)
start_server = websockets.serve(echo, "localhost", 8765)
asyncio.get_event_loop().run_until_complete(start_server)
asyncio.get_event_loop().run_forever()
本文来自博客园,作者:vx_guanchaoguo0,转载请注明原文链接:https://www.cnblogs.com/guanchaoguo/p/17799708.html

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