python 最简单的 websocket 会显服务

初次链接会显示 欢迎

import asyncio
import websockets

async def echo(websocket, path):
    # 发送 welcome 消息
    await websocket.send("welcome")
    
    async for message in websocket:
        await websocket.send(message)

start_server = websockets.serve(echo, "localhost", 8765)

asyncio.get_event_loop().run_until_complete(start_server)
asyncio.get_event_loop().run_forever()
posted @ 2023-10-31 10:30  vx_guanchaoguo0  阅读(17)  评论(0)    收藏  举报