问题描述:
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists.
代码如下: 6ms
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* struct ListNode *next;
* };
*/
struct ListNode* mergeTwoLists(struct ListNode* l1, struct ListNode* l2)
{
if(!l1 && !l2)
return NULL;
struct ListNode *pList = (struct ListNode *)malloc(sizeof(struct ListNode));
struct ListNode *pNode = NULL;
struct ListNode *pHead = pList;
while(l1 && l2)
{
pNode = (struct ListNode *)malloc(sizeof(struct ListNode));
if(l1->val < l2->val)
{
pNode->val = l1->val;
l1 = l1->next;
}
else
{
pNode->val = l2->val;
l2 = l2->next;
}
pNode->next = NULL;
pList->next = pNode;
pList = pNode;
}
while(l1)
{
pNode = (struct ListNode *)malloc(sizeof(struct ListNode));
pNode->val = l1->val;
pNode->next = NULL;
pList->next = pNode;
pList = pNode;
l1 = l1->next;
}
while(l2)
{
pNode = (struct ListNode *)malloc(sizeof(struct ListNode));
pNode->val = l2->val;
pNode->next = NULL;
pList->next = pNode;
pList = pNode;
l2 = l2->next;
}
return pHead->next;
}
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