问题描述:
Given an array and a value, remove all instances of that value in-place and return the new length.
Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.
The order of elements can be changed. It doesn't matter what you leave beyond the new length.
代码如下: 3ms
int removeElement(int* nums, int numsSize, int val)
{
int length = 0;
for(int i = 0;i<numsSize;++i)
{
if(nums[i] != val)
{
nums[length] = nums[i];
++length;
}
}
return length;
}
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