连续出现的字符
点击查看代码
#include<iostream>
#include<string>
using namespace std;
string s;
int main()
{
int n;
cin >> n; cin.ignore();
getline(cin, s);
int len = s.length();
int cnt = 1;
for (int i = 1; i < len; i++)
{
if (s[i] == s[i - 1])
{
cnt++;
if (cnt >= n)
{
cout << s[i];
return 0;
}
}
else
{
cnt = 1;
}
}
cout << "no" << endl;
return 0;
}

浙公网安备 33010602011771号