# [LeetCode] 841. Keys and Rooms 钥匙与房间

There are N rooms and you start in room 0.  Each room has a distinct number in 0, 1, 2, ..., N-1, and each room may have some keys to access the next room.

Formally, each room i has a list of keys rooms[i], and each key rooms[i][j] is an integer in [0, 1, ..., N-1] where N = rooms.length.  A key rooms[i][j] = v opens the room with number v.

Initially, all the rooms start locked (except for room 0).

You can walk back and forth between rooms freely.

Return true if and only if you can enter every room.

Example 1:

Input: [[1],[2],[3],[]]
Output: true
Explanation:
We start in room 0, and pick up key 1.
We then go to room 1, and pick up key 2.
We then go to room 2, and pick up key 3.
We then go to room 3.  Since we were able to go to every room, we return true.


Example 2:

Input: [[1,3],[3,0,1],[2],[0]]
Output: false
Explanation: We can't enter the room with number 2.


Note:

1. 1 <= rooms.length <= 1000
2. 0 <= rooms[i].length <= 1000
3. The number of keys in all rooms combined is at most 3000.

class Solution {
public:
bool canVisitAllRooms(vector<vector<int>>& rooms) {
unordered_set<int> visited{{0}};
queue<int> q{{0}};
while (!q.empty()) {
int t = q.front(); q.pop();
for (int key : rooms[t]) {
if (visited.count(key)) continue;
visited.insert(key);
if (visited.size() == rooms.size()) return true;
q.push(key);
}
}
return visited.size() == rooms.size();
}
};

class Solution {
public:
bool canVisitAllRooms(vector<vector<int>>& rooms) {
unordered_set<int> visited;
helper(rooms, 0, visited);
return visited.size() == rooms.size();
}
void helper(vector<vector<int>>& rooms, int cur, unordered_set<int>& visited) {
visited.insert(cur);
for (int key : rooms[cur]) {
if (!visited.count(key)) helper(rooms, key, visited);
}
}
};

Github 同步地址：

https://github.com/grandyang/leetcode/issues/841

https://leetcode.com/problems/keys-and-rooms/

https://leetcode.com/problems/keys-and-rooms/discuss/133944/Java-8-lines

https://leetcode.com/problems/keys-and-rooms/discuss/133855/Straight-Forward

LeetCode All in One 题目讲解汇总(持续更新中...)

posted @ 2019-02-21 22:33  Grandyang  阅读(2865)  评论(0编辑  收藏  举报