7. Reverse Integer 

 1 class Solution {
 2     public int reverse(int x) {
 3         long x2 = (long)x;
 4         if(x == 0) return 0;
 5         if(x2 < 0) {
 6             x2 = -x2;
 7             String str = "" + x2;
 8             StringBuilder sb = new StringBuilder(str);
 9             sb.reverse();
10             long x1 = Long.parseLong(sb.toString());
11             if(-x1 < Integer.MIN_VALUE) {
12                 return 0;
13             }else {
14                 return (int)-x1;
15             }
16         }else {
17             String str = "" + x;
18             StringBuilder sb = new StringBuilder(str);
19             sb.reverse();
20             long x1 = Long.parseLong(sb.toString());
21             if(x1 > Integer.MAX_VALUE) {
22                 return 0;
23             }else {
24                 return (int)x1;
25             }
26         }      
27         
28     }
29 }

 

posted @ 2018-09-26 04:21  jasoncool1  阅读(104)  评论(0)    收藏  举报