Problem A: 让动物们叫起来吧!
Description
Tom家里养了很多动物,比如有鸭子、火鸡和公鸡。它们的叫声都不相同。现在,请编写类Animal、Cock、Turkey和Duck,根据给出的main()函数及样例分析每个类的属性、行为及相互关系,以模仿Tom家的情况。
提示:动物们都有自己的名字。
Input
输入有多行。第一行正整数M表示之后有M个测试用例,每个测试用例包括2部分:前一部分是动物的名字,后一部分是动物的类型(用A、B、C分别表示鸭子、火鸡和公鸡)。
Output
输出有M行,每个测试用例对应一样。见样例。
Sample Input
3 Baby C Rubby B Tobby A
Sample Output
Baby is a cock, and it can crow. Rubby is a turkey, and it can gobble. Tobby is a duck, and it can quack.
HINT
Append Code
int main(){ int cases; string name; char type; Animal *animal; cin>>cases; for (int i = 0; i < cases; i++) { cin>>name>>type; switch(type) { case 'A': animal = new Duck(name); break; case 'B': animal = new Turkey(name); break; case 'C': animal = new Cock(name); break; } animal->sound(); } return 0;}代码
#include <iostream>using namespace std;class Animal{ public: Animal(){} virtual void sound(){}};class Cock:public Animal{ string name1;public: Cock(string n):name1(n){} void sound() { cout<<name1<<" is a cock, and it can crow."<<endl; }};class Turkey:public Animal{ string name2;public: Turkey(string n):name2(n){} void sound() { cout<<name2<<" is a turkey, and it can gobble."<<endl; }};class Duck:public Animal{ string name3;public: Duck(string n):name3(n){} void sound() { cout<<name3<<" is a duck, and it can quack."<<endl; }};int main(){ int cases; string name; char type; Animal *animal; cin>>cases; for (int i = 0; i < cases; i++) { cin>>name>>type; switch(type) { case 'A': animal = new Duck(name); break; case 'B': animal = new Turkey(name); break; case 'C': animal = new Cock(name); break; } animal->sound(); } return 0;}
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