用脚本实现在ASP.NET中“弹出信息窗口”及“控件获得焦点”的方法

///Common.cs
/// <summary>
/// 弹出的提示窗口。
/// </summary>
/// <param name="mssage">要提示的信息。</param>
/// <param name="p">当前网页的引用。</param>

public static void Alert(System.Web.UI.Page p,string mssage)
{
  string msg;
  msg  = "<script language='javascript'>";
  msg +="alert('" + mssage + "');";
  msg +="</script>";
  p.RegisterStartupScript("alert",msg);
}

/// <summary>
///　让控件获焦点。
/// </summary>
/// <param name="p">当前网页的引用。</param>
/// <param name="Control_ID">要获得焦点的控件在网页上的路径。</param>
/// <example>GetFocus(this,"TextBox1")</example>
  
public static void GetFocus(System.Web.UI.Page p,string Control_ID)
{
  string msg;
  msg  = "<script language='javascript'>";
  msg +="document.getElementById('"+ Control_ID +"').focus();";
  msg +="</script>";
  p.RegisterStartupScript("getFocus",msg);
}