<script type="text/javascript" src="jquery.js"></script>
<script type="text/javascript">
function doUpload(){
var oData = new FormData($('#uploadForm')[0]);
$.ajax({
url:"upload.php",
type:"post",
data:oData,
processData: false,
contentType: false,
cache: false,
success:function(obj){
var data = eval("("+obj+")");
if(data.code == 1){
$('#img_show').html('<img src="'+data.url+'" style="width:100px;height:100px;"/>');
}else{
alert(data.message);
}
}
});
}
</script>
<form id="uploadForm" enctype="multipart/form-data">
<p >上传文件: <input type="file" name="file"/></p>
<p><input type="button" value="上传" onclick="doUpload()"/> </p>
</form>
<div id="img_-show"></div>