Java 中 LinkedList 所有常用方法的示例代码和每个方法对应的输出 解释。

Java LinkedList 常用方法示例合集(含代码与输出)

 

1. add(E e):末尾添加元素

LinkedList<String> list = new LinkedList<>();
list.add("A");
list.add("B");
System.out.println(list);

输出:

[A, B]

 

2. add(int index, E element):指定位置添加元素

LinkedList<String> list = new LinkedList<>(Arrays.asList("A", "C"));
list.add(1, "B");
System.out.println(list);

输出:

B
[A, C]

 

C B A 

 

[A, B, C]

 

3. addAll(Collection c):末尾添加集合元素

LinkedList<String> list = new LinkedList<>(Arrays.asList("A"));
List<String> more = Arrays.asList("B", "C");
list.addAll(more);
System.out.println(list);

输出:

[A, B, C]

 

4. addAll(int index, Collection c):指定位置插入集合

LinkedList<String> list = new LinkedList<>(Arrays.asList("A", "D"));
List<String> toInsert = Arrays.asList("B", "C");
list.addAll(1, toInsert);
System.out.println(list);

输出:

[A, B, C, D]

 

5. addFirst(E e):添加到头部

LinkedList<String> list = new LinkedList<>(Arrays.asList("B", "C"));
list.addFirst("A");
System.out.println(list);

输出:

[A, B, C]

 

6. addLast(E e):添加到尾部
LinkedList<String> list = new LinkedList<>(Arrays.asList("A", "B"));
list.addLast("C");
System.out.println(list);

输出:

[A, B, C]

 

7. offer(E e):尾部添加元素,返回是否成功
LinkedList<String> list = new LinkedList<>();
boolean success = list.offer("X");
System.out.println(success);
System.out.println(list);

输出:

true
[X]

 

8. offerFirst(E e):头部插入元素
LinkedList<String> list = new LinkedList<>(Arrays.asList("B"));
list.offerFirst("A");
System.out.println(list);

输出:

[A, B]

 

9. offerLast(E e):尾部插入元素
LinkedList<String> list = new LinkedList<>(Arrays.asList("A"));
list.offerLast("B");
System.out.println(list);

输出:

[A, B]

 

10. clear():清空链表

LinkedList<String> list = new LinkedList<>(Arrays.asList("A", "B"));
list.clear();
System.out.println(list);

输出:

[]

 

11. removeFirst():删除并返回第一个元素

LinkedList<String> list = new LinkedList<>(Arrays.asList("A", "B"));
String removed = list.removeFirst();
System.out.println(removed);
System.out.println(list);

输出:

A
[B]

 

12. removeLast():删除并返回最后一个元素

LinkedList<String> list = new LinkedList<>(Arrays.asList("A", "B"));
String removed = list.removeLast();
System.out.println(removed);
System.out.println(list);

输出:

B
[A]

 

13. remove(Object o):删除指定对象
LinkedList<String> list = new LinkedList<>(Arrays.asList("A", "B", "C"));
boolean success = list.remove("B");
System.out.println(success);
System.out.println(list);

输出:

true
[A, C]

 

14. remove(int index):删除指定位置元素
LinkedList<String> list = new LinkedList<>(Arrays.asList("A", "B", "C"));
String removed = list.remove(1);
System.out.println(removed);
System.out.println(list);

输出:

B
[A, C]

 

15. poll():删除并返回第一个元素(为空返回 null)
LinkedList<String> list = new LinkedList<>(Arrays.asList("A", "B"));
String val = list.poll();
System.out.println(val);
System.out.println(list);

输出:

A
[B]

 

16. remove():删除并返回第一个元素(为空抛异常)
LinkedList<String> list = new LinkedList<>(Arrays.asList("A", "B"));
String val = list.remove();
System.out.println(val);
System.out.println(list);

输出:

A
[B]

 

17. contains(Object o):判断是否包含某元素
LinkedList<String> list = new LinkedList<>(Arrays.asList("A", "B"));
System.out.println(list.contains("A"));
System.out.println(list.contains("C"));

输出:

true
false

 

18. get(int index):获取指定位置的元素
LinkedList<String> list = new LinkedList<>(Arrays.asList("A", "B"));
System.out.println(list.get(1));

输出:

B

 

19. getFirst():返回第一个元素
LinkedList<String> list = new LinkedList<>(Arrays.asList("A", "B"));
System.out.println(list.getFirst());

输出:

A

 

20. getLast():返回最后一个元素
LinkedList<String> list = new LinkedList<>(Arrays.asList("A", "B"));
System.out.println(list.getLast());

输出:

B

 

21. indexOf(Object o):第一次出现的位置
LinkedList<String> list = new LinkedList<>(Arrays.asList("A", "B", "A"));
System.out.println(list.indexOf("A"));

输出:

0

 

22. lastIndexOf(Object o):最后一次出现的位置
LinkedList<String> list = new LinkedList<>(Arrays.asList("A", "B", "A"));
System.out.println(list.lastIndexOf("A"));

输出:

2

 

23. peek():返回第一个元素但不移除(为空返回 null)
LinkedList<String> list = new LinkedList<>(Arrays.asList("X", "Y"));
System.out.println(list.peek());

输出:

X 

 

24. element():返回第一个元素但不移除(为空抛异常)
LinkedList<String> list = new LinkedList<>(Arrays.asList("X", "Y"));
System.out.println(list.element());

输出:

X 

 

25. peekFirst():查看第一个元素(null 安全)
LinkedList<String> list = new LinkedList<>(Arrays.asList("A", "B"));
System.out.println(list.peekFirst());

输出:

A 

 

26. peekLast():查看最后一个元素(null 安全)
LinkedList<String> list = new LinkedList<>(Arrays.asList("A", "B"));
System.out.println(list.peekLast());

输出:

B 

 

27. set(int index, E element):设置指定位置元素
LinkedList<String> list = new LinkedList<>(Arrays.asList("A", "B", "C"));
list.set(1, "Z");
System.out.println(list);

输出:

[A, Z, C]

 

28. clone():克隆列表
LinkedList<String> list = new LinkedList<>(Arrays.asList("A", "B"));
LinkedList<String> cloned = (LinkedList<String>) list.clone();
System.out.println(cloned);

输出:

[A, B]

 

29. descendingIterator():返回倒序迭代器
LinkedList<String> list = new LinkedList<>(Arrays.asList("A", "B", "C"));
Iterator<String> it = list.descendingIterator();
while (it.hasNext()) {
    System.out.print(it.next() + " ");
}

输出:

C B A 

 

30. size():获取链表大小
LinkedList<String> list = new LinkedList<>(Arrays.asList("A", "B", "C"));
System.out.println(list.size());

输出:

3  

 

31. listIterator(int index):从指定位置返回迭代器
LinkedList<String> list = new LinkedList<>(Arrays.asList("A", "B", "C"));
ListIterator<String> it = list.listIterator(1);
while (it.hasNext()) {
    System.out.print(it.next() + " ");
}

输出:

B C 

 

32. toArray():转换为 Object 数组
LinkedList<String> list = new LinkedList<>(Arrays.asList("A", "B"));
Object[] arr = list.toArray();
System.out.println(Arrays.toString(arr));

输出:

[A, B]

 

33. toArray(T[] a):转换为指定类型数组
LinkedList<String> list = new LinkedList<>(Arrays.asList("A", "B"));
String[] arr = list.toArray(new String[0]);
System.out.println(Arrays.toString(arr));

输出:

[A, B]

 

 
posted @ 2025-08-01 11:05  AlphaGeek  阅读(46)  评论(0)    收藏  举报