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摘要: // 获取Url参数 function requestParam(paras) { var searchStr = location.search; var paramStr = searchStr.substring(searchStr.indexOf('?') + 1, searchStr.length).split('&'); var j; var paramObj = {}; for (var i = 0; j = paramStr[i]; i++) { paramOb... 阅读全文
posted @ 2012-08-08 16:34 TimGong 阅读(864) 评论(3) 推荐(1) 编辑