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Javascript获取Url请求参数

 

// 获取Url参数
function requestParam(paras) {
    var searchStr = location.search;
    var paramStr = searchStr.substring(searchStr.indexOf('?') + 1, searchStr.length).split('&');
    var j;
    var paramObj = {};
    for (var i = 0; j = paramStr[i]; i++) {
        paramObj[j.substring(0, j.indexOf('=')).toLowerCase()] = j.substring(j.indexOf('=') + 1, j.length);
    }
    var returnValue = paramObj[paras.toLowerCase()];
    if (typeof (returnValue) == "undefined") {
        return "";
    } else {
        return returnValue;
    }
}
posted @ 2012-08-08 16:34  TimGong  阅读(864)  评论(3编辑  收藏  举报