A matrix is Toeplitz if every diagonal from top-left to bottom-right has the same element.

Now given an M x N matrix, return True if and only if the matrix is Toeplitz.
 

Example 1:

Input: matrix = [[1,2,3,4],[5,1,2,3],[9,5,1,2]]
Output: True
Explanation:
1234
5123
9512

In the above grid, the diagonals are "[9]", "[5, 5]", "[1, 1, 1]", "[2, 2, 2]", "[3, 3]", "[4]", and in each diagonal all elements are the same, so the answer is True.

Example 2:

Input: matrix = [[1,2],[2,2]]
Output: False
Explanation:
The diagonal "[1, 2]" has different elements.

Note:

  1. matrix will be a 2D array of integers.
  2. matrix will have a number of rows and columns in range [1, 20].
  3. matrix[i][j] will be integers in range [0, 99].

解题思路:

  多重循环比较,感觉没有什么难点,不知道有没有更简单的方法。

 1 class Solution {
 2 public:
 3     bool isToeplitzMatrix(vector<vector<int>>& matrix) {
 4         int row = matrix.size();
 5         int column = matrix[0].size();
 6 
 7         for (int i = 0; i < row; i++) {
 8             for (int j = 0; j < column; j++) {
 9                 for (int m = i + 1, n = j + 1; m < row && n < column; m++, n++) {
10                     if (matrix[i][j] != matrix[m][n]) {
11                         return false;
12                     }
13                 }
14             }
15         }
16 
17         return true;
18     }
19 };