POJ 1742 hdu 2844 Coins

题目链接：http://poj.org/problem?id=1742

http://acm.hdu.edu.cn/showproblem.php?pid=2844

题目分类：动态规划

代码：

#include<stdio.h>
#include<string.h>
#include<math.h>
#include<algorithm>

using namespace std;
int n,m;
bool flag[100009];

struct P
{
    int a,b;

}point[200];

int cmp(P X,P Y)
{
    return X.a<Y.a;
}

int main()
{
    while(scanf("%d %d",&n,&m)&&(n+m))
    {
        memset(point,0,sizeof(point));
        memset(flag,0,sizeof(flag));

        for(int i=1;i<=n;i++)
        {
            scanf("%d",&point[i].a);
        }
        for(int i=1;i<=n;i++)
        {
            scanf("%d",&point[i].b);
        }
        sort(point+1,point+n+1,cmp);
        int sum[100005];

        flag[0]=1;
        for(int i=1;i<=n;i++)
        {
            memset(sum,0,sizeof(sum));
            for(int k=point[i].a;k<=m;k++)
            {
                if(flag[k-point[i].a]&&sum[k-point[i].a]<point[i].b&&!flag[k])
                {
                    sum[k] = sum[k-point[i].a] + 1;
                    flag[k] = 1;
                }
            }
        }

        int ans=0;
        for(int i=1;i<=m;i++)
        {
            if(flag[i])
            {
                //printf("sss==   %d\n",i);
                ans++;
            }
        }
        printf("%d\n",ans);
    }
    return 0;
}

 

#include<bits/stdc++.h>

using namespace std;

bool dp[100005];
int TmpVal[105];
int val[10005];

int main()
{
    cin.sync_with_stdio(false);
    cout.sync_with_stdio(false);
    int n, m;
    while(cin>>n>>m)
    {
        if(n==0 && m==0)
            break;
        memset(dp, 0, sizeof(dp));
        for(int i=1;i<=n;i++)
            cin>>TmpVal[i];
        int N = 0;
        for(int i=1;i<=n;i++)
        {
            int num;
            cin>>num;
            int j = 1;
            while(j<=num)
            {
                val[++N] = TmpVal[i] * j;
                num -= j;
                j = (j<<1);
            }
            if(num)
            {
                val[++N] = TmpVal[i] * num;
            }
        }
        dp[0] = 1;
        for(int i=1;i<=N;i++)
        {
            for(int j=m;j>=val[i];j--)
            {
                if(dp[j-val[i]])
                    dp[j] = 1;
            }
        }
        int ans = 0;
        for(int i=1;i<=m;i++)
            if(dp[i])
                ans++;
        printf("%d\n", ans);
    }
    return 0;
}