# 【Python 基础】列表中的元素排序例子

mylist = [3, 5, 2, 1, 8, 4]

mylist = [3, 5, 2, 1, 8, 4]

tester=0
lcount = len(mylist)

for x in range(lcount-1):
for y in range(x+1,lcount):
print("")
print ("x is: " + str (x) + " y is: " + str(y) )
print ("mylist[x] is: " + str ( mylist[x] ) + " mylist[y] is: " + str ( mylist[y] ) )
print(mylist)
##
if mylist[x]>mylist[y]:
mylist[x],mylist[y]=mylist[y],mylist[x]
print("exchanged")
else:
tester=1  ## Just to make if-else to end easily
print(mylist)

tester=0 ## Just to make the outer for cycle to end easily
print (mylist)

x is: 0 y is: 1
mylist[x] is: 3 mylist[y] is: 5
[3, 5, 2, 1, 8, 4]
[3, 5, 2, 1, 8, 4]

x is: 0 y is: 2
mylist[x] is: 3 mylist[y] is: 2
[3, 5, 2, 1, 8, 4]
exchanged
[2, 5, 3, 1, 8, 4]

x is: 0 y is: 3
mylist[x] is: 2 mylist[y] is: 1
[2, 5, 3, 1, 8, 4]
exchanged
[1, 5, 3, 2, 8, 4]

x is: 0 y is: 4
mylist[x] is: 1 mylist[y] is: 8
[1, 5, 3, 2, 8, 4]
[1, 5, 3, 2, 8, 4]

x is: 0 y is: 5
mylist[x] is: 1 mylist[y] is: 4
[1, 5, 3, 2, 8, 4]
[1, 5, 3, 2, 8, 4]

x is: 1 y is: 2
mylist[x] is: 5 mylist[y] is: 3
[1, 5, 3, 2, 8, 4]
exchanged
[1, 3, 5, 2, 8, 4]

x is: 1 y is: 3
mylist[x] is: 3 mylist[y] is: 2
[1, 3, 5, 2, 8, 4]
exchanged
[1, 2, 5, 3, 8, 4]

x is: 1 y is: 4
mylist[x] is: 2 mylist[y] is: 8
[1, 2, 5, 3, 8, 4]
[1, 2, 5, 3, 8, 4]

x is: 1 y is: 5
mylist[x] is: 2 mylist[y] is: 4
[1, 2, 5, 3, 8, 4]
[1, 2, 5, 3, 8, 4]

x is: 2 y is: 3
mylist[x] is: 5 mylist[y] is: 3
[1, 2, 5, 3, 8, 4]
exchanged
[1, 2, 3, 5, 8, 4]

x is: 2 y is: 4
mylist[x] is: 3 mylist[y] is: 8
[1, 2, 3, 5, 8, 4]
[1, 2, 3, 5, 8, 4]

x is: 2 y is: 5
mylist[x] is: 3 mylist[y] is: 4
[1, 2, 3, 5, 8, 4]
[1, 2, 3, 5, 8, 4]

x is: 3 y is: 4
mylist[x] is: 5 mylist[y] is: 8
[1, 2, 3, 5, 8, 4]
[1, 2, 3, 5, 8, 4]

x is: 3 y is: 5
mylist[x] is: 5 mylist[y] is: 4
[1, 2, 3, 5, 8, 4]
exchanged
[1, 2, 3, 4, 8, 5]

x is: 4 y is: 5
mylist[x] is: 8 mylist[y] is: 5
[1, 2, 3, 4, 8, 5]
exchanged
[1, 2, 3, 4, 5, 8]

[1, 2, 3, 4, 5, 8] <<<< 最终的结果

posted @ 2022-03-07 12:17  健哥的数据花园  阅读(71)  评论(0编辑  收藏  举报