next day

#_*_coding:utf_*_
#!/usr/bin/env python


now_day=input('当前某一天:').format('%Y.%m.%d')%%输入日期(年.月.日)

year=int(now_day.split('.')[0])%%年月日用符号“.”分隔开,年放在第一个位置
month=int(now_day.split('.')[1])%%月放在第二个位置
day=int(now_day.split('.')[2])%%日放在第三个位置
print(year,month,day)%%输出使用者
a=[1,3,5,7,8,10]%%将月份中有三十一天的列入一个数组
b=[4,6,9,11]%%将月份中只有三十天的列入一个数组
if month in a:%%如果月份属于a中,则判断日是否为三十一,不是则日加一,是则月加一
if day == 31:
month =int(month) + 1
day=1
print('%04d-%02d-%02d' % (year, month, day))
else:
if day < 32:
day = int(day) + 1
print('%04d-%02d-%02d' % (year, month, day))
elif month in b:%%如果月份属于b中,则判断日是否为三十,不是则日加一,是则月加一
if day == 30:
month = int(month)+ 1
day=1
print('%04d-%02d-%02d' % (year, month, day))
else:
if day < 32:
day = int(day) + 1
print('%04d-%02d-%02d' % (year, month, day))
elif month == 12 and day == 31:%%月份为12,日为31,则年加一
year = int(year) + 1
month=1
day=1
print('%04d-%02d-%02d' % (year, month, day))
elif month == 12 and day<32:%%月份为12,日小于31,则日加一
day = int(day) + 1
print('%04d-%02d-%02d' % (year, month, day))
elif month>12 or day>31:%%输入日期,月份大于12,日大于31,则输入错误
print('error input')
elif (year % 4) == 0 and (year % 100) != 0 or (year % 400) == 0:%%判断年是否为闰年,针对2月份来做约束
if month == 2 and day == 29:
month = int(month) + 1
day = 1
print('%04d-%02d-%02d' % (year, month, day))
else:
if day <32:
day = int(day) + 1
print('%04d-%02d-%02d' % (year, month, day))
else:
if month == 2 and day == 28:
month = int(month) + 1
day = 1
print('%04d-%02d-%02d' % (year, month, day))
else:
if day <32:
day = int(day) + 1
print('%04d-%02d-%02d' % (year, month, day))
posted @ 2018-12-31 12:00  gaofenzi  阅读(328)  评论(3)    收藏  举报