【leetcode】访问所有点的最小时间

 

int minTimeToVisitAllPoints(int** points, int pointsSize, int* pointsColSize){
    int sum=0,i;
    for (i=0; i<pointsSize-1; i++)
    {
        sum+= fmax(abs(points[i][0]-points[i+1][0]),abs(points[i][1]-points[i+1][1]));
    }
    return sum;
}

 

posted @ 2020-09-16 18:16  温暖了寂寞  阅读(136)  评论(0)    收藏  举报