【leetcode】 将数字变成 0 的操作次数
int numberOfSteps (int num){ int count=0; while(num) { num = (num % 2)? num^1 : num>>1; count++; } return count; }
int numberOfSteps (int num){ int count=0; while(num) { num = (num % 2)? num^1 : num>>1; count++; } return count; }