bzoj3382 [Usaco2004 Open]Cave Cows 3 洞穴里的牛之三

传送门:http://www.lydsy.com/JudgeOnline/problem.php?id=3382

【题解】

套路题。

首先我们会发现曼哈顿距离不好处理,难道要写kdtree???

(kdtree真的可以写啊qwq)

曼哈顿距离转成切比雪夫距离。

(x,y) ==> (x+y, x-y),那么就把坐标分离了。

然后对于每个坐标单独排序后求最大的差即可。

# include <stdio.h>
# include <string.h>
# include <iostream>
# include <algorithm>
// # include <bits/stdc++.h>

using namespace std;

typedef long long ll;
typedef long double ld;
typedef unsigned long long ull;
const int M = 5e4 + 10;
const int mod = 1e9+7;

# define RG register
# define ST static

int n;
int x[M], y[M], a[M], b[M];

int main() {
    cin >> n;
    for (int i=1; i<=n; ++i) scanf("%d%d", x+i, y+i);
    for (int i=1; i<=n; ++i) a[i] = x[i] + y[i], b[i] = x[i] - y[i];
    sort(a+1, a+n+1);
    sort(b+1, b+n+1);
    printf("%d\n", max(a[n]-a[1], b[n]-b[1]));
    return 0;
}
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posted @ 2017-05-16 10:47  Galaxies  阅读(156)  评论(0编辑  收藏