摘要： with redraw off 阅读全文

摘要： superclassof meditMaterials[1]map_sample =renderMap meditMaterials[1] size:[200,200] scale:200TestMapSamples.bmp_slot1.bitmap =map_sample 阅读全文

摘要： rollout unnamedRollout "Untitled" width:162 height:300( button btn1 "Button" pos:[35,48] width:73 height:80 on btn1 pressed do ( DestroyDialog unnamedRollout for i in 1 to 199 do print i CreateDialog unnamedRollout )) CreateDialog unnamedRollout 阅读全文

摘要： MaxString = "abcdefg"DotNetString = DotNetObject "System.String" MaxString DotNetString.Replace "a" "z" --返回值就是MaxScript中的StringDotNetString.toString() --从.net中取值 阅读全文

摘要： for i in 1 to 10 do ( for a in 1 to 30 do ( if a == 10 do exit print a ) print i ) 阅读全文

摘要： fn save_by_Group sel dir = ( local ss = #(), s for i in sel where isGroupHead i do ( setGroupOpen i false append ss i ) for i in ss do ( s = for o in i.children collect i append s i saveNodes s (dir+i.name+".max") quiet:on ))save_by_Group objects "d:\\" 阅读全文

摘要： 如果两个平面只是方向不同的话，它们与射线的交点应该是相等的吧？下面算法计算出来的不相等吧？　平面方程为Ax + By + Cz + D = 0; 平面的单位法向量为N(A, B, C);射线表示为P = Org +Dir*step; Dir为射线的方向，已经规格化。Org为原点把射线的方程代入平面方程可以得step = -(DotProduct(N, Org)+D)/(DotProduct(N, Dir);平面的参数如下：A = 1; B = 0; C = 0; D = -7;A = -1;B = 0; C = 0; ... 阅读全文

摘要： meditMaterials[3].showInViewport= true meditMaterials[3].showInViewport= falseokMtlForScene $.materialshowHWTextureMap $.material trueenableHardwareMaterial $.material false 阅读全文

摘要： IViewportShadingMgr.ReviewGPUDiagnostics() 阅读全文

摘要： modPanel.setCurrentObject $.baseObject 阅读全文