LL(1)文法的判断,递归下降分析程序
1. 文法 G(S):
(1)S -> AB
(2)A ->Da|ε
(3)B -> cC
(4)C -> aADC |ε
(5)D -> b|ε
验证文法 G(S)是不是 LL(1)文法?
答:
FIRST集:
FIRST(Da) = {b, a }
FIRST(ɛ) = { ɛ }
FIRST(aADC) = { a }
FIRST(b) = { b }
FOLLOW集:
FOLLOW(A) = { c,b,a , # }
FOLLOW(B)
FOLLOW(D),FIRST(C) ,FOLLOW(C)
FOLLOW(C) = { #}
FOLLOW(D) = { a , # }
SELECT集:
SELECT(A → Da) = {b, a }
SELECT(A→ ε) = {c,b,a , # }
SELECT(A→Da) ∩ SELECT(A→ ε)≠∅
表达式文法不是LL(1)文法
2.(上次作业)消除左递归之后的表达式文法是否是LL(1)文法?
E → TE'
E' → +TE' | ɛ
T → FT' | ɛ
T' → *FT' | ɛ
F → (E) | i
答:
SELECT(E' → +TE' ) = FIRST(+TE') ={ + }
SELECT(E' → ε) = FOLLOW(E')={ #,) }
SELECT(T' → *FT') = FIRST(*FT') ={ * }
SELECT(T' → ε) =FOLLOW(T')={ #,),+ }
SELECT(F → (E) ) =FIRST((E)) ={ ( }
SELECT(F → i) = FIRST(i) ={ i }
SELECT(E' → +TE') ∩ SELECT(E' → ε)=∅
SELECT(T' → *FT') ∩ SELECT(T' → ε)=∅
SELECT(F → (E)) ∩ SELECT(F → i)=∅
表达式文法是LL(1)文法
3.接2,如果是LL(1)文法,写出它的递归下降语法分析程序代码。
E()
{T();
E'();
}
E'()
T()
T'()
F()
SELECT(E → TE') = FIRST(TE') ={(,i,* }
SELECT(E' → +TE' ) = FIRST(+TE') ={ + }
SELECT(E' → ε) = FOLLOW(E')={ #,) }
SELECT(T → FT') = FIRST(FT') ={(,i }
SELECT(T' → *FT') = FIRST(*FT') ={ * }
SELECT(T' → ε) =FOLLOW(T')={ #,),+ }
SELECT(F → (E) ) =FIRST((E)) ={ ( }
SELECT(F → i) = FIRST(i) ={ i }
void ParseE(){
switch(lookahead){
case (,i:
ParseT();
ParseE1();
break;
default:
printf("syntax error \n");
exit(0);
}
}
void ParseE'(){
switch(lookahead){
case +:
MatchToken(+);
ParseT();
ParseE1();
break;
case #,):
break;
default:
printf("syntax error \n");
exit(0);
}
}
void ParseT(){
switch(lookahead){
case (,i:
ParseF();
ParseT1();
break;
default:
printf("syntax error \n");
exit(0);
}
}
void ParseT'(){
switch(lookahead){
case *:
MatchToken(*);
ParseF();
ParseT1();
break;
case #,),+:
break;
default:
printf("syntax error \n");
exit(0);
}
}
void ParseF(){
switch(lookahead){
case (:
MatchToken(();
ParseE();
MatchToken());
break;
case i:
MatchToken(i);
break;
default:
printf("syntax error \n");
exit(0);
}
}
4.加上实验一的词法分析程序,形成可运行的语法分析程序,分析任意输入的符号串是不是合法的表达式。

浙公网安备 33010602011771号