leetcode 832 翻转图像

package com.example.lettcode.dailyexercises;

/**
 * @Class FlipAndInvertImage
 * @Description 832 翻转图像
 * 给定一个二进制矩阵 A,我们想先水平翻转图像,然后反转图像并返回结果。
 * 水平翻转图片就是将图片的每一行都进行翻转,即逆序。例如,水平翻转 [1, 1, 0] 的结果是 [0, 1, 1]。
 * 反转图片的意思是图片中的 0 全部被 1 替换, 1 全部被 0 替换。例如,反转 [0, 1, 1] 的结果是 [1, 0, 0]。
 * <p>
 * 示例 1:
 * 输入:[[1,1,0],[1,0,1],[0,0,0]]
 * 输出:[[1,0,0],[0,1,0],[1,1,1]]
 * 解释:首先翻转每一行: [[0,1,1],[1,0,1],[0,0,0]];
 * 然后反转图片: [[1,0,0],[0,1,0],[1,1,1]]
 * <p>
 * 示例 2:
 * 输入:[[1,1,0,0],[1,0,0,1],[0,1,1,1],[1,0,1,0]]
 * 输出:[[1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0]]
 * 解释:首先翻转每一行: [[0,0,1,1],[1,0,0,1],[1,1,1,0],[0,1,0,1]];
 * 然后反转图片: [[1,1,0,0],[0,1,1,0],[0,0,0,1],[1,0,1,0]]
 * <p>
 * 提示:
 * 1 <= A.length = A[0].length <= 20
 * 0 <= A[i][j] <= 1
 * @Author
 * @Date 2021/2/24
 **/
public class FlipAndInvertImage {
    public static int[][] flipAndInvertImage(int[][] A) {
        if (A == null || A.length == 0 || A[0].length == 0) return A;
        int[][] cloneArray = A.clone();
        int row = cloneArray.length;
        int col = cloneArray[0].length;
        for (int j = 0; j < col / 2; j++) {
            for (int i = 0; i < row; i++) {
                if (cloneArray[i][j] == 0) cloneArray[i][j] = 1;
                else cloneArray[i][j] = 0;
                if (cloneArray[i][col - j - 1] == 0) cloneArray[i][col - j - 1] = 1;
                else cloneArray[i][col - j - 1] = 0;

                cloneArray[i][j] = cloneArray[i][j] + cloneArray[i][col - j - 1];
                cloneArray[i][col - j - 1] = cloneArray[i][j] - cloneArray[i][col - j - 1];
                cloneArray[i][j] = cloneArray[i][j] - cloneArray[i][col - j - 1];
            }
        }
        if (col % 2 != 0) {
            for (int i = 0; i < row; i++) {
                if (cloneArray[i][col / 2] == 0) cloneArray[i][col / 2] = 1;
                else cloneArray[i][col / 2] = 0;
            }
        }

        return cloneArray;
    }
}
// 测试用例
public static void main(String[] args) {
	int[][] A = new int[][]{{1, 1, 0}, {1, 0, 1}, {0, 0, 0}};
	int[][] ans = FlipAndInvertImage.flipAndInvertImage(A);
	System.out.println("FlipAndInvertImage demo01:");
	for (int i = 0; i < ans.length; i++) {
		System.out.println("");
		for (int j = 0; j < ans[0].length; j++) {
			System.out.print("," + ans[i][j]);
		}
	}
	System.out.println("");

	A = new int[][]{{1, 1, 0, 0}, {1, 0, 0, 1}, {0, 1, 1, 1}, {1, 0, 1, 0}};
	ans = FlipAndInvertImage.flipAndInvertImage(A);
	System.out.println("FlipAndInvertImage demo02:");
	for (int i = 0; i < ans.length; i++) {
		System.out.println("");
		for (int j = 0; j < ans[0].length; j++) {
			System.out.print("," + ans[i][j]);
		}
	}
	System.out.println("");
}
posted @ 2021-02-24 15:43  枫叶艾辰  阅读(65)  评论(0)    收藏  举报