获取网站资源 getResourceAsStream

    获取网站资源(重点)
public void doGet(HttpServletRequest request, HttpServletResponse response)throws ServletException, IOException {
        // 获取网站对象
        ServletContext context = this.getServletContext();
        // 获取网站中的静态资源
        InputStream in = context.getResourceAsStream("/123.bmp");
        // 获取输出流
        FileOutputStream out = new FileOutputStream(new File("d:/123.bmp"));
        // 边读 边写
        byte[] bs  = new byte[1024];
        int len = 0;
        while((len = in.read(bs)) != -1){
            out.write(bs, 0, len);
            out.flush();
        }
        // 释放资源
        in.close();
        out.close();
    }