链接:https://oj.leetcode.com/problems/swap-nodes-in-pairs/
交换链表相邻的节点的位置
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution
{
public:
ListNode *swapPairs(ListNode *head)
{
ListNode *ans=new ListNode(0);
ans->next=head;
head=ans; //添加哨兵
if(ans->next==NULL||ans->next->next==NULL)
return ans->next;
ans=ans->next->next;
while(head->next&&head->next->next)
{
ListNode *last=head->next->next;
head->next->next=last->next;
last->next=head->next;
head->next=last;
head=last->next;
}
return ans;
}
};
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