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2015-04-11 15:25  笨笨的老兔子  阅读(150)  评论(0)    收藏  举报

给定一个n*n的二维向量，顺时针旋转90度

  1. class Solution {
  2. public:
  3.     void rotate(vector<vector<int> > &matrix) {
  4.         int length = matrix.size();
  5.         for (int i = 0; i < length/2; i++)
  6.         {
  7.             for (int j = i; j < length  - i - 1; j++)
  8.             {
  9.                 int tmp = matrix[i][j];
  10.                 matrix[i][j] = matrix[length - j - 1][i];
  11.                 matrix[length - j - 1][i] = matrix[length - i - 1][length - j - 1];
  12.                 matrix[length - i - 1][length - j - 1] = matrix[j][length - i - 1];
  13.                 matrix[j][length - i - 1] = tmp;
  14.             }
  15.         }
  16.     }
  17. };