python-day06_02 for循环&range对象

# ### for循环
# 遍历 循环 迭代 , 把容器中的元素一个一个获取出来

# while循环在遍历数据时的局限性
"""
lst = [1,2,3,4,5]  # ok
i = 0
while i < len(lst):
    print(lst[i])
    i+=1
    
setvar = {"a","b","c"} # not ok
i = 0
while i < len(setvar):
    print(setvar[i])
    i+=1
"""

# for循环的基本语法
"""
Iterable 可迭代性数据：1.容器类型数据 2.range对象 3.迭代器
for 变量 in Iterable:
    code1.
"""
# 字符串
container = "北京和深圳温差大概20多度"
# 列表
container = [1,2,3,4,4,5]
# 元组
container = ("孙开洗","孙健","孙悟空")
# 集合 
container = {"陈璐","曹静怡","王志国","邓鹏","合力"}
# 字典
container = {"cl":"风流倜傥","cjy":"拳击选手","wzg":"寻花问柳","dp":"帅气,祖国的栋梁","hl":"你是个好人"}

# 遍历数据
for i in container:
    print(i)

print("<===================>")
# 1.遍历不等长多级容器
container = [1,2,3,4,("嗄","234",{"马春配","李虎凌","刘子涛"})]
for i in container:
    # 判断当前元素是否是容器,如果是,进行二次遍历,如果不是,直接打印
    if isinstance(i,tuple):
        # ("嗄","234",{"马春配","李虎凌","刘子涛"})
        for j in i:
            # 判断当前元素是否是集合,如果是,进行三次遍历,如果不是,直接打印
            if isinstance(j,set):
                # j = {"马春配","李虎凌","刘子涛"}
                for k in j :
                    print(k)
            else:
                print(j)
                
    # 打印数据
    else:
        print(i)

# 2.遍历不等长多级容器
container = [("刘玉波","历史源","张光旭"), ("上朝气","于朝志"),("韩瑞晓",)]
for i in container:
    for j in i:
        print(j)


# 3.遍历等长的容器
container = [("马云","小马哥","马春配") , ["王健林","王思聪","王志国"],{"王宝强","马蓉","宋小宝"}]
for a,b,c in container:
    print(a,b,c)

# 变量的解包
a,b,c = "poi"
a,b = (1,2)
a,b = 1,2
a,b,c = [10,11,12]
a,b = {"林明辉","家率先"}
a,b = {"lmh":"林明辉","jsx":"家率先"}
a,b,c = ("马云","小马哥","马春配")
print(a,b,c)

# ### range对象
"""
range([开始值,]结束值[,步长])
取头舍尾,结束值本身获取不到,获取到它之前的那一个数据
"""

# range(一个值)
for i in range(5): # 0 ~ 4
    print(i)

# range(二个值)
for i in range(3,8): # 3 4 5 6 7 
    print(i)

# range(三个值) 正向的从左到右
for i in range(1,11,3): # 1 4 7 10 
    print(i)

# range(三个值) 逆向的从右到左
for i in range(10,0,-1): # 10 9 8 7 ... 1 
    print(i)


# 总结:
"""
while 一般用于处理复杂的逻辑关系
for   一般用于迭代数据
部分情况下两个循环可以互相转换;
"""

i = 1
while i <= 9:
    j = 1
    while j <= i:
        print("%d*%d=%2d " % (i,j,i*j) ,end="" )
        j+=1
    print()    
    i +=1

for i in range(1,10):
    for j in range(1,i+1):
        print("%d*%d=%2d " % (i,j,i*j) ,end="" )
    print()

# 打印 1 ~ 10 跳过5
i = 1
while i <= 10:    
    if i == 5:
        i += 1
        continue
    print(i)
    i +=1
    
for i in range(1,11):
    if i == 5:
        continue
    print(i)