key不在这里

key不在这里

附件是一张二维码图片

扫描得到m=10210897103375566531005253102975053545155505050521025256555254995410298561015151985150375568

发现这串字符是经过URL编码再转换成ASCII码，通过脚本解出flag{5d45fa256372224f48746c6fb8e33b32}

from urllib.parse import quote, unquote
s = '10210897103375566531005253102975053545155505050521025256555254995410298561015151985150375568'
temp = ''
 
while len(s):
    if int(s[:3]) < 127:
        temp += chr(int(s[:3]))
        s = s[3:]
    else:
        temp += chr(int(s[:2]))
        s = s[2:]
print(temp)
print(unquote(temp))