利用循环removeChild删除节点只删除一半问题
<!DOCTYPE html> <html> <head> <title>adduser.html</title> <meta http-equiv="keywords" content="keyword1,keyword2,keyword3"> <meta http-equiv="description" content="this is my page"> <meta http-equiv="content-type" content="text/html; charset=UTF-8"> <!--<link rel="stylesheet" type="text/css" href="./styles.css">--> <script type="text/javascript" src="../js/append1.js"></script> </head> <body > <div align="center"> <div>添加联系人</div> <input type="text" name="name">姓名<br/> <input type="text" name="phone">电话<br/> <input type="text" name="mail">邮箱<br/> <input type="button" onclick="add()" value="提交"> </div> <hr> <div align="center"> <table border="1" cellspacing="0" id="table"> <tr id="Button"> <td colspan="4" align="center"> <input type="button" value="全选" onclick=All()> <input type="button" value="反选" onclick=other()> <input type="button" value="删除" onclick=Delete()> </td> </tr> <tr> <td><input name="items" type="checkbox" ></td> <td>李四</td> <td>1361888234</td> <td>ab@sina.com</td> </tr> </table> </div> </body> </html> |
function add(){ var Node_name=document.getElementsByName("name")[0]; var Node_phone=document.getElementsByName("phone")[0]; var Node_mail=document.getElementsByName("mail")[0]; var Element_tr=document.createElement("tr"); var select_td=document.createElement("td"); var input_node=document.createElement("input"); input_node.setAttribute("name","items"); input_node.setAttribute("type", "checkbox"); select_td.appendChild(input_node); var name_td=document.createElement("td"); var name_text=document.createTextNode(Node_name.value); name_td.appendChild(name_text); var phone_td=document.createElement("td"); var phone_text=document.createTextNode(Node_phone.value); phone_td.appendChild(phone_text); var mail_td=document.createElement("td"); var mail_text=document.createTextNode(Node_mail.value); mail_td.appendChild(mail_text); Element_tr.appendChild(select_td); Element_tr.appendChild(name_td); Element_tr.appendChild(phone_td); Element_tr.appendChild(mail_td); var Element_table=document.getElementById("table"); Element_table.appendChild(Element_tr); } function All(){ var check_node=document.getElementsByName("items"); for ( var i = 0; i < check_node.length; i++) { check_node[i].checked="checked"; } } function other(){ var check_node=document.getElementsByName("items"); for ( var i = 0; i < check_node.length; i++) { if(check_node[i].checked){ check_node[i].checked=null; }else{ check_node[i].checked="checked"; } } } function Delete(){ var check_node=document.getElementsByName("items"); //alert(check_node.length); for ( var i = 0; i < check_node.length; i++) { if(check_node[i].checked){ //alert(check_node[i].checked); var delete_tr_node=check_node[i].parentNode.parentNode; //alert(delete_tr_node.nodeName); var Element_table=document.getElementById("table"); Element_table.removeChild(delete_tr_node); } } }For循环颠倒一下就可以了，现在循环是从小到大，改成从大到小就可以了,因为数组长度在变化
