2019-5-8训练

http://codeforces.com/problemset/problem/1144/E

26进制，任意进制的做法

 1 #include<iostream>
 2 #include<cstdio>
 3 #include<cmath>
 4 #include<algorithm>
 5 using namespace std;
 6 typedef long long ll;
 7 int k;
 8 char aa[200010];
 9 char bb[200010];
10 int a[200010];
11 int b[200010];
12 int zz[200010];
13 int ans[200010];
14 int main()
15 {
16     cin >> k;
17     for (int i = 1; i <= k; i++)
18     {
19         cin >> aa[i];
20         a[i] = int(aa[i] - 'a');
21     }
22     for (int i = 1; i <= k; i++)
23     {
24         cin >> bb[i];
25         b[i] = int(bb[i] - 'a');
26     }
27     for (int i = k; i >=1; i--)
28     {
29         if (b[i] >= a[i])
30         {
31             zz[i] = b[i] - a[i];
32         }
33         else
34         {
35             zz[i] = b[i] + 26 - a[i];
36             b[i - 1]--;
37         }
38     }
39     for (int i = 1; i <= k; i++)
40     {
41         if (zz[i] % 2 == 0)
42         {
43             ans[i] = zz[i] / 2;
44         }
45         else
46         {
47             ans[i] = (zz[i] - 1) / 2;
48             zz[i + 1] = zz[i + 1] + 26;
49         }
50     }
51     for (int i = k; i >= 1; i--)
52     {
53         if (ans[i] + a[i] >= 26)
54         {
55             ans[i] = ans[i] + a[i] - 26;
56             ans[i - 1]++;
57         }
58         else
59         {
60             ans[i] = ans[i] + a[i];
61         }
62     }
63     for (int i = 1; i <= k; i++)
64     {
65         printf("%c", char(ans[i]+'a'));
66     }
67     return 0;
68 }

 

posted @ 2019-05-09 00:42  Fzzf1  阅读(158)  评论(0)  编辑  收藏  举报