实验6

实验任务4

源代码

#include <stdio.h>
#include <string.h>
#define N 10

typedef struct{
    char isbn[20];
    char name[80];
    char author[80];
    double sales_price;
    int sales_count;
}Book;

void output(Book x[],int n);
void sort(Book x[],int n);
double sales_amount(Book x[],int n);

int main(){
    Book x[N]={
        {"978-7-5327-6082-4","门将之死","罗纳德.伦",42,51},
        {"978-7-308-17047-5","自由与爱之地：入以色列记","云也退",49,30},
        {"978-7-5404-9344-8","伦敦人","克莱格泰勒",68,27},
        {"978-7-5447-5246-6","软件体的生命周期","特德姜",35,90},
        {"978-7-5722-5475-8","芯片简史","汪波",74.9,49},
        {"978-7-5133-5750-0","主机战争","布莱克.J.哈里斯",128,42},
        {"978-7-2011-4617-1","世界尽头的咖啡馆","约翰·史崔勒基",22.5,44},
        {"978-7-5133-5109-6","你好外星人","英国未来出版集团",118,42},
        {"978-7-1155-0509-5","无穷的开始：世界进步的本源","戴维·多伊奇",37.5,55},
        {"978-7-229-14156-1","源泉","安.兰德",84,59}
    };

    printf("图书销量排名(按销售册数)：\n");
    sort(x,N);
    output(x,N);
    printf("\n图书销售总额：%.2f\n",sales_amount(x, N));

    return 0;
}


void output(Book x[],int n){
    printf("%-20s %-30s %-20s %-10s %s\n","ISBN","书名","作者","售价","销售册数");
    int i,j;
    for(i=0;i<n;i++){
        printf("%-20s %-30s %-20s %-10.1f %d\n",x[i].isbn,x[i].name,x[i].author,x[i].sales_price,x[i].sales_count);
    }
}


void sort(Book x[],int n){
	int i,j;
    for(i=0;i<n-1;i++){
        for(j=0;j<n-i-1;j++){
            if (x[j].sales_count<x[j+1].sales_count) {
                Book temp=x[j];
                x[j]=x[j+1];
                x[j+1]=temp;
            }
        }
    }
}


double sales_amount(Book x[],int n){
    double total=0.0;
    int i,j;
    for(i=0;i<n;i++){
        total+=x[i].sales_price*x[i].sales_count;
    }
    return total;
}

运行结果

实验任务5

源代码

#include <stdio.h>

typedef struct {
int year;
int month;
int day;
}Date;

void input(Date *pd);
int day_of_year(Date d);
int compare_dates(Date d1,Date d2);

void test1(){
Date d;
int i;

printf("输入日期:(以形如2025-12-19这样的形式输入)\n");
for(i=0;i<3;++i){
    input(&d);
    printf("%d-%02d-%02d是这一年中第%d天\n\n",d.year,d.month,d.day,day_of_year(d));
}
}

void test2(){
Date Alice_birth,Bob_birth;
int i;
int ans;

printf("输入Alice和Bob出生日期:(以形如2025-12-19这样的形式输入)\n");
for(i=0;i<3;++i){
    input(&Alice_birth);
    input(&Bob_birth);
    ans=compare_dates(Alice_birth,Bob_birth);

    if(ans==0)
    printf("Alice和Bob一样大\n\n");
    else if(ans==-1)
    printf("Alice比Bob大\n\n");
    else
    printf("Alice比Bob小\n\n");
}
}

int main(){
printf("测试1:输入日期,打印输出这是一年中第多少天\n");
test1();

printf("\n测试2:两个人年龄大小关系\n");
test2();

return 0;
}

void input(Date *pd){
scanf("%d-%d-%d",&pd->year,&pd->month,&pd->day);
}

int day_of_year(Date d){
int month_days[]={0,31,28,31,30,31,30,31,31,30,31,30,31};
int total_days=0;
int i;

if((d.year%4==0&&d.year%100!=0)||(d.year%400==0)){
    month_days[2]=29;
}

for(i=1;i<d.month;i++){
    total_days+=month_days[i];
}
total_days+=d.day;

return total_days;
}

int compare_dates(Date d1,Date d2){
if(d1.year<d2.year){
    return -1;
}else if(d1.year>d2.year){
    return 1;
}else{
    if(d1.month<d2.month){
        return -1;
    }else if(d1.month>d2.month){
        return 1;
    }else{
        if(d1.day<d2.day){
            return -1;
        }else if(d1.day>d2.day){
            return 1;
        }else{
            return 0;
        }
    }
}
}

运行结果

实验任务6

源代码

#include <stdio.h>
#include <string.h>

enum Role{admin,student,teacher};

typedef struct {
char username[20];
char password[20];
enum Role type;
}Account;

void output(Account x[],int n);

int main(){
Account x[]={{"A1001","123456",student},
{"A1002","123abcdef",student},
{"A1009","xyz12121",student},
{"X1009","9213071x",admin},
{"C11553","129dfg32k",teacher},
{"X3005","921kfmg917",student}};
int n;
n=sizeof(x)/sizeof(Account);
output(x,n);
return 0;
}

void output(Account x[],int n){
int i,j;
int len;
char role_name[20];

for(i=0;i<n;i++){
    printf("%-10s",x[i].username);
    len=strlen(x[i].password);
    for(j=0;j<len;j++){
        printf("*");
    }
    for(;j<15;j++){
        printf(" ");
    }
    switch(x[i].type){
        case admin:strcpy(role_name,"admin");break;
        case student:strcpy(role_name,"student");break;
        case teacher:strcpy(role_name,"teacher");break;
        default:strcpy(role_name,"unknown");
    }
    printf("%s\n",role_name);
}
}

运行结果

实验任务7

源代码

#include <stdio.h>
#include <string.h>

typedef struct {
char name[20];
char phone[12];
int vip;
}Contact;

void set_vip_contact(Contact x[],int n,char name[]);
void output(Contact x[],int n);
void display(Contact x[],int n);

#define N 10

int main(){
Contact list[N]={{"刘一","15510846604",0},
{"陈二","18038747351",0},
{"张三","18853253914",0},
{"李四","13230584477",0},
{"王五","15547571923",0},
{"赵六","18856659351",0},
{"周七","17705843215",0},
{"孙八","15552933732",0},
{"吴九","18077702405",0},
{"郑十","18820725036",0}};
int vip_cnt,i;
char name[20];

printf("显示原始通讯录信息：\n");
output(list,N);

printf("\n输入要设置的紧急联系人个数：");
scanf("%d",&vip_cnt);
printf("输入%d个紧急联系人姓名：\n",vip_cnt);
for(i=0;i<vip_cnt;++i){
    scanf("%s",name);
    set_vip_contact(list,N,name);
}

printf("\n显示通讯录列表：(按姓名字典升序排列，紧急联系人最先显示)\n");
display(list,N);

return 0;
}

void set_vip_contact(Contact x[],int n,char name[]){
int i;
for(i=0;i<n;i++){
    if(strcmp(x[i].name,name)==0){
        x[i].vip=1;
        break;
    }
}
}

void output(Contact x[],int n){
int i;
for(i=0;i<n;++i){
    printf("%-10s%s",x[i].name,x[i].phone);
    if(x[i].vip){
        printf("*");
    }
    printf("\n");
}
}

void display(Contact x[],int n){
int i,j;
Contact temp;
Contact sorted[N];

for(i=0;i<n;i++){
    sorted[i]=x[i];
}

for(i=0;i<n-1;i++){
    for(j=0;j<n-i-1;j++){
        if(sorted[j].vip==sorted[j+1].vip){
            if(strcmp(sorted[j].name,sorted[j+1].name)>0){
                temp=sorted[j];
                sorted[j]=sorted[j+1];
                sorted[j+1]=temp;
            }
        }else if(sorted[j].vip<sorted[j+1].vip){
            temp=sorted[j];
            sorted[j]=sorted[j+1];
            sorted[j+1]=temp;
        }
    }
}

for(i=0;i<n;i++){
    printf("%-10s%s",sorted[i].name,sorted[i].phone);
    if(sorted[i].vip){
        printf("      *");
    }
    printf("\n");
}
}

运行结果