leetcode -- Gray Code

The gray code is a binary numeral system where two successive values differ in only one bit.

Given a non-negative integer n representing the total number of bits in the code, print the sequence of gray code. A gray code sequence must begin with 0.

For example, given n = 2, return [0,1,3,2]. Its gray code sequence is:

00 - 0
01 - 1
11 - 3
10 - 2

Note:
For a given n, a gray code sequence is not uniquely defined.

For example, [0,2,3,1] is also a valid gray code sequence according to the above definition.

For now, the judge is able to judge based on one instance of gray code sequence. Sorry about that.

[解题思路]

000
001
011
010
110
111 
101
100

 1 public class Solution {
 2     public ArrayList<Integer> grayCode(int n) {
 3         // Start typing your Java solution below
 4         // DO NOT write main() function
 5         ArrayList<Integer> result = new ArrayList<Integer>();
 6         if(n <= 1){
 7             result.add(0);
 8             if(n == 1){
 9                 result.add(1);
10             }
11             return result;
12         }
13         
14         ArrayList<Integer> pre = grayCode(n - 1);
15         int highest = 1 << (n - 1);
16         result.addAll(pre);
17         for(int i = pre.size() - 1; i >= 0 ; i --){
18             result.add(pre.get(i) + highest);
19         }
20         return result;
21     }
22 }

解2:

二进制码->格雷码(编码):从最右边一位起,依次将每一位与左边一位异或(XOR),作为对应格雷码该位的值,最左边一位不变(相当于左边是0);
格雷码->二进制码(解码):从左边第二位起,将每位与左边一位解码后的值异或,作为该位解码后的值(最左边一位依然不变)。

 1 public ArrayList<Integer> grayCode(int n) {
 2         // Start typing your Java solution below
 3         // DO NOT write main() function
 4         ArrayList<Integer> result = new ArrayList<Integer>();
 5         int count = 1 << n;
 6         for(int i = 0; i < count; i++){
 7             result.add(i^(i >> 1));
 8         }
 9         
10         return result;
11     }

 

posted @ 2013-08-11 22:55  feiling  阅读(472)  评论(0编辑  收藏  举报