查询最近每天的总和，即查询结果的数量

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SELECT
			SUM(secondLuckNumber) ,#每天字段secondLuckNumber的和
			DATE_FORMAT(time, '%Y%m%d') days
		FROM
			records
		GROUP BY
			days DESC  #从最新开始显示

SELECT
	count(*)
FROM
	(
		SELECT
			SUM(secondLuckNumber) - SUM(firstLuckNumber) + count(firstLuckNumber),
			DATE_FORMAT(time, '%Y%m%d') days
		FROM
			records
		GROUP BY
			days DESC
	) AS tmp

#统计上述查询结果的数量