例2.13数据分组

def bifurcate_by(L,fn):
    return [[x for x in L if fn(x)],
                [x for x in L if not fn(x)]]
s = bifurcate_by(['beep','boop','foo','bar'],lambda x: x[0] == 'b')
print(s)

print("学号：3008")

结果如下图