动态数组的输入

char array_num[100] ;
int i = 0, length;
do
{
scanf("%c", &array_num[i]);
i++;
} while (array_num[i - 1] != '\n');
length = i-1;

int *k;
for()
{
scanf("%d",&n);
k=new int[n];
}

posted @ 2021-03-26 11:54  戴上痛苦面具的菜鸡  阅读(272)  评论(0)    收藏  举报