python 快速把 url 的参数 转变成 字典的脚本

```

params = 'ct=24&qqmusic_ver=1298&new_json=1&remoteplace=txt.yqq.top&searchid=68258480754143850&t=0&aggr=1&cr=1&catZhida=1&lossless=0&flag_qc=0&p=1&n=10&w=%E5%91%A8%E6%9D%B0%E4%BC%A6&_=1634005892719&cv=4747474&ct=24&format=json&inCharset=utf-8&outCharset=utf-8&notice=0&platform=yqq.json&needNewCode=0&uin=0&g_tk_new_20200303=5381&g_tk=5381&hostUin=0&loginUin=0'

dist={}

for i in params.split('&'):

    item=i.split('=')

    dist[item[0]]=item[1]

print(dist)

```