python 实例四

题目：输入某年某月某日，判断这一天是这一年的第几天？

程序分析：

月份天数：

月份	天数
2	平年28天，闰年29天
1,3,5,7,8,10,12	31
4,6,9,11	30

 

 闰年：

1、非整百年：能被4整除的为闰年。（如2004年就是闰年,2100年不是闰年）

 

2、整百年：能被400整除的是闰年。(如2000年是闰年，1900年不是闰年)

>>> L=[31,31,30,31,30,31,31,30,31,30,31]
>>> def caldate(a,b,c):
	s=0
	if(a%100!=0 and a%4==0 or a%100==0 and a%400==0):
		L.insert(1,29)
	else:
		L.insert(1,28)
	for i in range(b-1):
		s=s+L[i]
	return s+c

>>> caldate(2016,1,2)
2
>>> caldate(2016,3,2)
62

改进版：考虑了月份和天数的有效性（哈哈，对比网上的答案，一看自己的代码就像是菜鸟级的，还有很多需要学习的地方）

def caldate(a,b,c):
	L=[31,31,30,31,30,31,31,30,31,30,31]
	s=0
	Leap=0
	if(a%100!=0 and a%4==0 or a%100==0 and a%400==0):
		L.insert(1,29)
		Leap=1
	else:
		L.insert(1,28)
	if 0<b<=12:
		if 0<c<=31:
			if((b==2)and(Leap==1)and(c<=29)or((b==2)and(Leap==0)and(c<=28))):
				for i in range(b-1):
					s=s+L[i]
					return s+c
			else:
				print 'The February should not greater than 28 or 29'
		else:
			print 'The date is error'
	else:
		print 'The month is invalid'

输出：

>>> caldate(2016,4,33)
The date is error
>>> caldate(2017,2,30)
The February should not greater than 28 or 29
>>> caldate(2017,2,28)
59
>>> caldate(2017,2,29)
The February should not greater than 28 or 29
>>> caldate(2017,13,29)
The month is invalid

网上答案：

#!/usr/bin/python
# -*- coding: UTF-8 -*-
 
year = int(raw_input('year:\n'))
month = int(raw_input('month:\n'))
day = int(raw_input('day:\n'))
 
months = (0,31,59,90,120,151,181,212,243,273,304,334)
if 0 < month <= 12:
    sum = months[month - 1]
else:
    print 'data error'
sum += day
leap = 0
if (year % 400 == 0) or ((year % 4 == 0) and (year % 100 != 0)):
    leap = 1
if (leap == 1) and (month > 2):
    sum += 1
print 'it is the %dth day.' % sum

 输出结果：

year:
2015
month:
6
day:
7
it is the 158th day.