剑指offer09 用两个栈实现队列

题目

用两个栈实现一个队列。队列的声明如下,请实现它的两个函数 appendTail 和 deleteHead ,分别完成在队列尾部插入整数和在队列头部删除整数的功能。(若队列中没有元素,deleteHead 操作返回 -1 )

示例 1:
输入:
["CQueue","appendTail","deleteHead","deleteHead"]
[[],[3],[],[]]
输出:[null,null,3,-1]

示例 2:
输入:
["CQueue","deleteHead","appendTail","appendTail","deleteHead","deleteHead"]
[[],[],[5],[2],[],[]]
输出:[null,-1,null,null,5,2]

提示:
1 <= values <= 10000
最多会对 appendTail、deleteHead 进行 10000 次调用

方法

  • 时间复杂度:O(1),插入为O(1),删除虽然有时是O(n),但均摊下来是O(1)
  • 空间复杂度:O(n)
class CQueue {
    private Stack<Integer> pushStack ;
    private Stack<Integer> popStack;

    public CQueue() {
        this.pushStack = new Stack();
        this.popStack = new Stack();

    }
    
    public void appendTail(int value) {
        pushStack.push(value);
    }
    
    public int deleteHead() {
        if(popStack.isEmpty()){
            while(!pushStack.isEmpty()){
                popStack.push(pushStack.pop());
            }
        }
        if(popStack.isEmpty()){
            return -1;
        }
        return popStack.pop();
    }
}
posted @ 2021-08-10 20:55  你也要来一颗长颈鹿吗  阅读(26)  评论(0)    收藏  举报