Oracle 拆分列为多行 Splitting string into multiple rows in Oracle

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The table is as follows:

Name | Project | Error 
108    test      Err1, Err2, Err3
109    test2     Err1

I want to create the following:

Name | Project | Error
108    Test      Err1
108    Test      Err2 
108    Test      Err3 
109    Test2     Err1

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Solution 1

This may be an improved way (also with regexp and connect by):

with temp as
(
    select 108 Name, 'test' Project, 'Err1, Err2, Err3' Error  from dual
    union all
    select 109, 'test2', 'Err1' from dual
)
select distinct
  t.name, t.project,
  trim(regexp_substr(t.error, '[^,]+', 1, levels.column_value))  as error
from 
  temp t,
  table(cast(multiset(select level from dual connect by  level <= length (regexp_replace(t.error, '[^,]+'))  + 1) as sys.OdciNumberList)) levels
order by name

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Solution 2

with temp as  (
       select 108 Name, 'test' Project, 'Err1, Err2, Err3' Error  from dual
       union all
       select 109, 'test2', 'Err1' from dual
     )

SELECT distinct Name, Project, trim(regexp_substr(str, '[^,]+', 1, level)) str
  FROM (SELECT Name, Project, Error str FROM temp) t
CONNECT BY instr(str, ',', 1, level - 1) > 0
order by Name

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REF
https://stackoverflow.com/questions/14328621/splitting-string-into-multiple-rows-in-oracle
https://stackoverflow.com/questions/38371989/how-to-convert-comma-separated-values-to-rows-in-oracle


 

posted @ 2019-09-03 17:39 emanlee 阅读(...) 评论(...) 编辑 收藏